How to solve 10 - 3 + 2q / 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 10 - 3 + 2q / 2 | Equatix

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Question

$$10-3+2\times q\div2$$

Evaluate

$q+7$

Show Solution

Differentiate w.r.t. q

$1$

Steps Using Derivative Rule for Sum

Subtract $3$ from $10$ to get $7$.

$$\frac{\mathrm{d}}{\mathrm{d}q}(7+\frac{2q}{2})$$

Cancel out $2$ and $2$.

$$\frac{\mathrm{d}}{\mathrm{d}q}(7+q)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$q^{1-1}$$

Subtract $1$ from $1$.

$$q^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

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Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. q

Steps Using Derivative Rule for Sum