How to solve 10-5+3x-6=10x+10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 10-5+3x-6=10x+10 | Equatix

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Question

$$10-5+3x-6=10x+10$$

Solve for x

$x = -\frac{11}{7} = -1\frac{4}{7} \approx -1.571428571$

Steps for Solving Linear Equation

Subtract $5$ from $10$ to get $5$.

$$5+3x-6=10x+10$$

Subtract $6$ from $5$ to get $-1$.

$$-1+3x=10x+10$$

Subtract $10x$ from both sides.

$$-1+3x-10x=10$$

Combine $3x$ and $-10x$ to get $-7x$.

$$-1-7x=10$$

Add $1$ to both sides.

$$-7x=10+1$$

Add $10$ and $1$ to get $11$.

$$-7x=11$$

Divide both sides by $-7$.

$$x=\frac{11}{-7}$$

Fraction $\frac{11}{-7}$ can be rewritten as $-\frac{11}{7}$ by extracting the negative sign.

$$x=-\frac{11}{7}$$

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Question

Solve for x

Steps for Solving Linear Equation