Solve 10-6(8x-2)=9x-(3+4x] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$10-6(8x-2)=9x-(3+4x]$$

Solve for x

$x=\frac{25}{53}\approx 0.471698113$

Steps for Solving Linear Equation

Use the distributive property to multiply $-6$ by $8x-2$.

$$10-48x+12=9x-\left(3+4x\right)$$

Add $10$ and $12$ to get $22$.

$$22-48x=9x-\left(3+4x\right)$$

To find the opposite of $3+4x$, find the opposite of each term.

$$22-48x=9x-3-4x$$

Combine $9x$ and $-4x$ to get $5x$.

$$22-48x=5x-3$$

Subtract $5x$ from both sides.

$$22-48x-5x=-3$$

Combine $-48x$ and $-5x$ to get $-53x$.

$$22-53x=-3$$

Subtract $22$ from both sides.

$$-53x=-3-22$$

Subtract $22$ from $-3$ to get $-25$.

$$-53x=-25$$

Divide both sides by $-53$.

$$x=\frac{-25}{-53}$$

Fraction $\frac{-25}{-53}$ can be simplified to $\frac{25}{53}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{25}{53}$$