How to solve 10 + 10; - 10!

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 10 + 10; - 10! | Equatix

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$$10+10; -10!$$

$-10,-5,20,150$

Add $10$ and $10$ to get $20$.

$$sort(20,-10,15\times 10,-5)$$

Multiply $15$ and $10$ to get $150$.

$$sort(20,-10,150,-5)$$

To sort the list, start from a single element $20$.

$$20$$

Insert $-10$ to the appropriate location in the new list.

$$-10,20$$

Insert $150$ to the appropriate location in the new list.

$$-10,20,150$$

Insert $-5$ to the appropriate location in the new list.

$$-10,-5,20,150$$

$20,\ -10,\ 150,\ -5$