How to solve 10+18/38 imes10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 10+18/38\times10 | Equatix

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$$10+18/38 \times 10$$

$\frac{280}{19}\approx 14.736842105$

Reduce the fraction $\frac{18}{38}$ to lowest terms by extracting and canceling out $2$.

$$10+\frac{9}{19}\times 10$$

Express $\frac{9}{19}\times 10$ as a single fraction.

$$10+\frac{9\times 10}{19}$$

Multiply $9$ and $10$ to get $90$.

$$10+\frac{90}{19}$$

Convert $10$ to fraction $\frac{190}{19}$.

$$\frac{190}{19}+\frac{90}{19}$$

Since $\frac{190}{19}$ and $\frac{90}{19}$ have the same denominator, add them by adding their numerators.

$$\frac{190+90}{19}$$

Add $190$ and $90$ to get $280$.

$$\frac{280}{19}$$

$\frac{2 ^ {3} \cdot 5 \cdot 7}{19} = 14\frac{14}{19} = 14.736842105263158$