$$10+(-3)2+3 \times (-5-5) \times 6 \div 2$$
$-86$
$$10-6+\frac{3\left(-5-5\right)\times 6}{2}$$
$$4+\frac{3\left(-5-5\right)\times 6}{2}$$
$$4+\frac{3\left(-10\right)\times 6}{2}$$
$$4+\frac{-30\times 6}{2}$$
$$4+\frac{-180}{2}$$
$$4-90$$
$$-86$$
Show Solution
Hide Solution
