$$10 \quad 025 ( 4 f - 3 ) = 0.05 ( 10 f - 9 )$$
$f=0.9$
$$0\times 25\left(4f-3\right)=0.05\left(10f-9\right)$$
$$0\left(4f-3\right)=0.05\left(10f-9\right)$$
$$0=0.05\left(10f-9\right)$$
$$0=0.5f-0.45$$
$$0.5f-0.45=0$$
$$0.5f=0.45$$
$$f=\frac{0.45}{0.5}$$
$$f=\frac{45}{50}$$
$$f=\frac{9}{10}$$
Show Solution
Hide Solution
