1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$10 \times \frac { 2 } { 9 } \times \frac { 6 } { 5 }$$

$\frac{8}{3}\approx 2.666666667$

Express $10\times \frac{2}{9}$ as a single fraction.

$$\frac{10\times 2}{9}\times \frac{6}{5}$$

Multiply $10$ and $2$ to get $20$.

$$\frac{20}{9}\times \frac{6}{5}$$

Multiply $\frac{20}{9}$ times $\frac{6}{5}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{20\times 6}{9\times 5}$$

Do the multiplications in the fraction $\frac{20\times 6}{9\times 5}$.

$$\frac{120}{45}$$

Reduce the fraction $\frac{120}{45}$ to lowest terms by extracting and canceling out $15$.

$$\frac{8}{3}$$

$\frac{2 ^ {3}}{3} = 2\frac{2}{3} = 2.6666666666666665$