How to solve 101011 * 101011

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 101011 * 101011 | Equatix

Question

$$101011\times101011$$

Evaluate

$10203222121$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times9999}101011\\\underline{\times\phantom{9999}101011}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 101011 with 1. Write the result 101011 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}101011\\\underline{\times\phantom{9999}101011}\\\phantom{\times9999}101011\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 101011 with 1. Write the result 101011 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}101011\\\underline{\times\phantom{9999}101011}\\\phantom{\times9999}101011\\\phantom{\times999}101011\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 101011 with 0. Write the result 0 at the end leaving 2 spaces to the right like this.

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 101011 with 1. Write the result 101011 at the end leaving 3 spaces to the right like this.

Now multiply the first number with the $5^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 101011 with 0. Write the result 0 at the end leaving 4 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}101011\\\underline{\times\phantom{9999}101011}\\\phantom{\times9999}101011\\\phantom{\times999}101011\phantom{9}\\\phantom{\times99999999}0\phantom{99}\\\phantom{\times9}101011\phantom{999}\\\phantom{\times999999}0\phantom{9999}\\\end{array}$$

Now multiply the first number with the $6^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 101011 with 1. Write the result 101011 at the end leaving 5 spaces to the right like this.

Now add the intermediate results to get final answer.

Show Solution

Factor

$83^{2}\times 1217^{2}$

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Steps For Long Multiplication

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