How to solve 10h+21=15-2h

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 10h+21=15-2h | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$10h+21=15-2h$$

Solve for h

$h=-\frac{1}{2}=-0.5$

Steps for Solving Linear Equation

Add $2h$ to both sides.

$$10h+21+2h=15$$

Combine $10h$ and $2h$ to get $12h$.

$$12h+21=15$$

Subtract $21$ from both sides.

$$12h=15-21$$

Subtract $21$ from $15$ to get $-6$.

$$12h=-6$$

Divide both sides by $12$.

$$h=\frac{-6}{12}$$

Reduce the fraction $\frac{-6}{12}$ to lowest terms by extracting and canceling out $6$.

$$h=-\frac{1}{2}$$

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Question

Solve for h

Steps for Solving Linear Equation