Question

$$[11-20\div(5^{2}-13)-\overline{3+8}]\times2$$

Answer

$$[11-5/3-3*e^2*IM*o*v*r*l*n+8]*2$$

Solution


Simplify  \({5}^{2}\)  to  \(25\).
\(11-\frac{20}{25-13}-overl\imath ne\times 3+8\)*2
Simplify  \(25-13\)  to  \(12\).
\(11-\frac{20}{12}-overl\imath ne\times 3+8\)*2
Simplify  \(\frac{20}{12}\)  to  \(\frac{5}{3}\).
\(11-\frac{5}{3}-overl\imath ne\times 3+8\)*2
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\(11-\frac{5}{3}-ov{e}^{2}rl\imath n\times 3+8\)*2
Regroup terms.
\(11-\frac{5}{3}-3{e}^{2}\imath ovrln+8\)*2