$$11-52=-\frac{2}{3}(3+z)$$
$z = \frac{117}{2} = 58\frac{1}{2} = 58.5$
$$-41=-\frac{2}{3}\left(3+z\right)$$
$$-41=-\frac{2}{3}\times 3-\frac{2}{3}z$$
$$-41=-2-\frac{2}{3}z$$
$$-2-\frac{2}{3}z=-41$$
$$-\frac{2}{3}z=-41+2$$
$$-\frac{2}{3}z=-39$$
$$z=-39\left(-\frac{3}{2}\right)$$
$$z=\frac{-39\left(-3\right)}{2}$$
$$z=\frac{117}{2}$$
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