How to solve 11-5x+3x+4x=18

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 11-5x+3x+4x=18 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$11-5x+3x+4x=18$$

Solve for x

$x = \frac{7}{2} = 3\frac{1}{2} = 3.5$

Steps for Solving Linear Equation

Combine $-5x$ and $3x$ to get $-2x$.

$$11-2x+4x=18$$

Combine $-2x$ and $4x$ to get $2x$.

$$11+2x=18$$

Subtract $11$ from both sides.

$$2x=18-11$$

Subtract $11$ from $18$ to get $7$.

$$2x=7$$

Divide both sides by $2$.

$$x=\frac{7}{2}$$

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Question

Solve for x

Steps for Solving Linear Equation