$$117 \div 45+(81-18) \div 9$$
$\frac{48}{5}=9.6$
$$\frac{13}{5}+\frac{81-18}{9}$$
$$\frac{13}{5}+\frac{63}{9}$$
$$\frac{13}{5}+7$$
$$\frac{13}{5}+\frac{35}{5}$$
$$\frac{13+35}{5}$$
$$\frac{48}{5}$$
Show Solution
Hide Solution
$\frac{2 ^ {4} \cdot 3}{5} = 9\frac{3}{5} = 9.6$