How to solve 11X - 14 > 8X + 6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 11X - 14 > 8X + 6 | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$11X-14>8X+6$$

Solve for X

$X>\frac{20}{3}$

Solution Steps

Subtract $8X$ from both sides.

$$11X-14-8X>6$$

Combine $11X$ and $-8X$ to get $3X$.

$$3X-14>6$$

Add $14$ to both sides.

$$3X>6+14$$

Add $6$ and $14$ to get $20$.

$$3X>20$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$X>\frac{20}{3}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for X

Solution Steps