$$12 { x }^{ 3 } +4 { x }^{ 2 } +3x+8-y=16 { x }^{ 3 } -6 { x }^{ 2 } +5x+11$$
$y=-4x^{3}+10x^{2}-2x-3$
$$4x^{2}+3x+8-y=16x^{3}-6x^{2}+5x+11-12x^{3}$$
$$4x^{2}+3x+8-y=4x^{3}-6x^{2}+5x+11$$
$$3x+8-y=4x^{3}-6x^{2}+5x+11-4x^{2}$$
$$3x+8-y=4x^{3}-10x^{2}+5x+11$$
$$8-y=4x^{3}-10x^{2}+5x+11-3x$$
$$8-y=4x^{3}-10x^{2}+2x+11$$
$$-y=4x^{3}-10x^{2}+2x+11-8$$
$$-y=4x^{3}-10x^{2}+2x+3$$
$$\frac{-y}{-1}=\frac{4x^{3}-10x^{2}+2x+3}{-1}$$
$$y=\frac{4x^{3}-10x^{2}+2x+3}{-1}$$
$$y=-4x^{3}+10x^{2}-2x-3$$
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