How to solve 12 * 4 = 8ix

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12 * 4 = 8ix | Equatix

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$$12\cdot4=8\ ix$$

$x=-6i$

Multiply $12$ and $4$ to get $48$.

$$48=8ix$$

Swap sides so that all variable terms are on the left hand side.

$$8ix=48$$

Divide both sides by $8i$.

$$x=\frac{48}{8i}$$

Multiply both numerator and denominator of $\frac{48}{8i}$ by imaginary unit $i$.

$$x=\frac{48i}{8i^{2}}$$

By definition, $i^{2}$ is $-1$. Calculate the denominator.

$$x=\frac{48i}{-8}$$

Divide $48i$ by $-8$ to get $-6i$.

$$x=-6i$$