How to solve 12-6/4+3=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12-6/4+3= | Equatix

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Question

$$12-6/4+3=$$

Evaluate

$\frac{27}{2}=13.5$

Solution Steps

Reduce the fraction $\frac{6}{4}$ to lowest terms by extracting and canceling out $2$.

$$12-\frac{3}{2}+3$$

Convert $12$ to fraction $\frac{24}{2}$.

$$\frac{24}{2}-\frac{3}{2}+3$$

Since $\frac{24}{2}$ and $\frac{3}{2}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{24-3}{2}+3$$

Subtract $3$ from $24$ to get $21$.

$$\frac{21}{2}+3$$

Convert $3$ to fraction $\frac{6}{2}$.

$$\frac{21}{2}+\frac{6}{2}$$

Since $\frac{21}{2}$ and $\frac{6}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{21+6}{2}$$

Add $21$ and $6$ to get $27$.

$$\frac{27}{2}$$

Show Solution

Factor

$\frac{3 ^ {3}}{2} = 13\frac{1}{2} = 13.5$