How to solve 12+3-8+3-5-6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12+3-8+3-5-6 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$12+3-8+3-5-6$$

Evaluate

$-1$

Solution Steps

Add $12$ and $3$ to get $15$.

$$15-8+3-5-6$$

Subtract $8$ from $15$ to get $7$.

$$7+3-5-6$$

Add $7$ and $3$ to get $10$.

$$10-5-6$$

Subtract $5$ from $10$ to get $5$.

$$5-6$$

Subtract $6$ from $5$ to get $-1$.

$$-1$$

Show Solution

Factor

$-1$

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