Solve 12+[3+(14\div3)-(-3+22)] | Equatix

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Question

$$12+[3+(14 \div 3)-(-3+22)]$$

Evaluate

$\frac{2}{3}\approx 0.666666667$

Solution Steps

Convert $3$ to fraction $\frac{9}{3}$.

$$12+\frac{9}{3}+\frac{14}{3}-\left(-3+22\right)$$

Since $\frac{9}{3}$ and $\frac{14}{3}$ have the same denominator, add them by adding their numerators.

$$12+\frac{9+14}{3}-\left(-3+22\right)$$

Add $9$ and $14$ to get $23$.

$$12+\frac{23}{3}-\left(-3+22\right)$$

Add $-3$ and $22$ to get $19$.

$$12+\frac{23}{3}-19$$

Convert $19$ to fraction $\frac{57}{3}$.

$$12+\frac{23}{3}-\frac{57}{3}$$

Since $\frac{23}{3}$ and $\frac{57}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$12+\frac{23-57}{3}$$

Subtract $57$ from $23$ to get $-34$.

$$12-\frac{34}{3}$$

Convert $12$ to fraction $\frac{36}{3}$.

$$\frac{36}{3}-\frac{34}{3}$$

Since $\frac{36}{3}$ and $\frac{34}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{36-34}{3}$$

Subtract $34$ from $36$ to get $2$.

$$\frac{2}{3}$$

Show Solution

Factor

$\frac{2}{3} = 0.6666666666666666$