How to solve 12+4(2x+4)=68

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12+4(2x+4)=68 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$12+4(2x+4)=68$$

Solve for x

$x=5$

Steps for Solving Linear Equation

Use the distributive property to multiply $4$ by $2x+4$.

$$12+8x+16=68$$

Add $12$ and $16$ to get $28$.

$$28+8x=68$$

Subtract $28$ from both sides.

$$8x=68-28$$

Subtract $28$ from $68$ to get $40$.

$$8x=40$$

Divide both sides by $8$.

$$x=\frac{40}{8}$$

Divide $40$ by $8$ to get $5$.

$$x=5$$

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Question

Solve for x

Steps for Solving Linear Equation