How to solve 12 imes365

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12\times365 | Equatix

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Question

$$12 \times 365$$

Evaluate

$4380$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}365}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 12 with 5. Write the result 60 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}365}\\\phantom{\times99}60\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 12 with 6. Write the result 72 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}365}\\\phantom{\times99}60\\\phantom{\times9}72\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 12 with 3. Write the result 36 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}365}\\\phantom{\times99}60\\\phantom{\times9}72\phantom{9}\\\underline{\phantom{\times}36\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}365}\\\phantom{\times99}60\\\phantom{\times9}72\phantom{9}\\\underline{\phantom{\times}36\phantom{99}}\\\phantom{\times}4380\end{array}$$

Show Solution

Factor

$2^{2}\times 3\times 5\times 73$