How to solve 12 imes41

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12\times41 | Equatix

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Question

$$12 \times 41$$

Evaluate

$492$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times9}12\\\underline{\times\phantom{9}41}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 12 with 1. Write the result 12 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9}12\\\underline{\times\phantom{9}41}\\\phantom{\times9}12\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 12 with 4. Write the result 48 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9}12\\\underline{\times\phantom{9}41}\\\phantom{\times9}12\\\underline{\phantom{\times}48\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times9}12\\\underline{\times\phantom{9}41}\\\phantom{\times9}12\\\underline{\phantom{\times}48\phantom{9}}\\\phantom{\times}492\end{array}$$

Show Solution

Factor

$2^{2}\times 3\times 41$