$$120000= \frac{ CL }{ \frac{ 2 }{ } } -3QA$$
$\left\{\begin{matrix}A=\frac{CL-240000}{6Q}\text{, }&Q\neq 0\\A\in \mathrm{R}\text{, }&C=\frac{240000}{L}\text{ and }L\neq 0\text{ and }Q=0\end{matrix}\right.$
$\left\{\begin{matrix}C=\frac{6\left(AQ+40000\right)}{L}\text{, }&L\neq 0\\C\in \mathrm{R}\text{, }&Q=-\frac{40000}{A}\text{ and }A\neq 0\text{ and }L=0\end{matrix}\right.$
