Question

$$121a^{-10b^{-15}\div11a-3b^{-8}$$

Answer

$$(11*b^-15)/a^9-3*b^-8$$

Solution


Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[121\times \frac{1}{{a}^{10}}\times \frac{{b}^{-15}}{11}a-3{b}^{-8}\]
Simplify  \(121\times \frac{1}{{a}^{10}}\times \frac{{b}^{-15}}{11}a\)  to  \(\frac{121{b}^{-15}a}{11{a}^{10}}\).
\[\frac{121{b}^{-15}a}{11{a}^{10}}-3{b}^{-8}\]
Take out the constants.
\[\frac{121}{11}\times \frac{{b}^{-15}a}{{a}^{10}}-3{b}^{-8}\]
Simplify  \(\frac{121}{11}\)  to  \(11\).
\[11\times \frac{{b}^{-15}a}{{a}^{10}}-3{b}^{-8}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[11{b}^{-15}{a}^{1-10}-3{b}^{-8}\]
Simplify  \(1-10\)  to  \(-9\).
\[11{b}^{-15}{a}^{-9}-3{b}^{-8}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[11{b}^{-15}\times \frac{1}{{a}^{9}}-3{b}^{-8}\]
Simplify  \(11{b}^{-15}\times \frac{1}{{a}^{9}}\)  to  \(\frac{11{b}^{-15}}{{a}^{9}}\).
\[\frac{11{b}^{-15}}{{a}^{9}}-3{b}^{-8}\]