Solve 12q - 17 - (- q) - 11 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$12q-17-(-q)-11$$

Evaluate

$13q-28$

Solution Steps

Multiply $-1$ and $-1$ to get $1$.

$$12q-17+q-11$$

Combine $12q$ and $q$ to get $13q$.

$$13q-17-11$$

Subtract $11$ from $-17$ to get $-28$.

$$13q-28$$

Differentiate w.r.t. q

$13$

Steps Using Derivative Rule for Sum

Multiply $-1$ and $-1$ to get $1$.

$$\frac{\mathrm{d}}{\mathrm{d}q}(12q-17+q-11)$$

Combine $12q$ and $q$ to get $13q$.

$$\frac{\mathrm{d}}{\mathrm{d}q}(13q-17-11)$$

Subtract $11$ from $-17$ to get $-28$.

$$\frac{\mathrm{d}}{\mathrm{d}q}(13q-28)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$13q^{1-1}$$

Subtract $1$ from $1$.

$$13q^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$13\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$13$$