How to solve 12x+4[6-(3x+2)]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12x+4[6-(3x+2)] | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$12x+4[6-(3x+2)]$$

Evaluate

$16$

Solution Steps

To find the opposite of $3x+2$, find the opposite of each term.

$$12x+4\left(6-3x-2\right)$$

Subtract $2$ from $6$ to get $4$.

$$12x+4\left(4-3x\right)$$

Use the distributive property to multiply $4$ by $4-3x$.

$$12x+16-12x$$

Combine $12x$ and $-12x$ to get $0$.

$$16$$

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Factor

$2^{4}$

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