How to solve 12xyz(08)^(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12xyz(08)^(2) | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$12xyz { \left(08 \right) }^{ 2 }$$

Evaluate

$0$

Solution Steps

Multiply $0$ and $8$ to get $0$.

$$12xyz\times 0^{2}$$

Calculate $0$ to the power of $2$ and get $0$.

$$12xyz\times 0$$

Multiply $12$ and $0$ to get $0$.

$$0xyz$$

Anything times zero gives zero.

$$0$$

Show Solution

Factor

$0$

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