How to solve 13 > 8 < 125

Q: How to solve 13 > 8 < 125

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 13 > 8 < 125 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

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$$13 > 8 < 125$$

Verify

$\text{true}$

Solution Steps

Compare $13$ and $8$.

$$\text{true}\text{ and }8<125$$

Compare $8$ and $125$.

$$\text{true}\text{ and }\text{true}$$

The conjunction of $\text{true}$ and $\text{true}$ is $\text{true}$.

$$\text{true}$$

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