How to solve 13-7x <= 8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 13-7x <= 8 | Equatix

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$$13-7x \leq 8$$

$x\geq \frac{5}{7}$

Subtract $13$ from both sides.

$$-7x\leq 8-13$$

Subtract $13$ from $8$ to get $-5$.

$$-7x\leq -5$$

Divide both sides by $-7$. Since $-7$ is negative, the inequality direction is changed.

$$x\geq \frac{-5}{-7}$$

Fraction $\frac{-5}{-7}$ can be simplified to $\frac{5}{7}$ by removing the negative sign from both the numerator and the denominator.

$$x\geq \frac{5}{7}$$