$$13-(3-1\frac{20}{21}):\frac{4}{49}+\frac{3}{10}$$
$\frac{7}{15}\approx 0.466666667$
$$13-\frac{3-\frac{21+20}{21}}{\frac{4}{49}}+\frac{3}{10}$$
$$13-\frac{3-\frac{41}{21}}{\frac{4}{49}}+\frac{3}{10}$$
$$13-\frac{\frac{63}{21}-\frac{41}{21}}{\frac{4}{49}}+\frac{3}{10}$$
$$13-\frac{\frac{63-41}{21}}{\frac{4}{49}}+\frac{3}{10}$$
$$13-\frac{\frac{22}{21}}{\frac{4}{49}}+\frac{3}{10}$$
$$13-\frac{22}{21}\times \frac{49}{4}+\frac{3}{10}$$
$$13-\frac{22\times 49}{21\times 4}+\frac{3}{10}$$
$$13-\frac{1078}{84}+\frac{3}{10}$$
$$13-\frac{77}{6}+\frac{3}{10}$$
$$\frac{78}{6}-\frac{77}{6}+\frac{3}{10}$$
$$\frac{78-77}{6}+\frac{3}{10}$$
$$\frac{1}{6}+\frac{3}{10}$$
$$\frac{5}{30}+\frac{9}{30}$$
$$\frac{5+9}{30}$$
$$\frac{14}{30}$$
$$\frac{7}{15}$$
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$\frac{7}{3 \cdot 5} = 0.4666666666666667$
