Solve 14(2t - 3) - 2(t + 2) = 10(3t - 4) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$14(2t-3)-2(t+2)=10(3t-4)$$

Solve for t

$t = -\frac{3}{2} = -1\frac{1}{2} = -1.5$

Steps for Solving Linear Equation

Use the distributive property to multiply $14$ by $2t-3$.

$$28t-42-2\left(t+2\right)=10\left(3t-4\right)$$

Use the distributive property to multiply $-2$ by $t+2$.

$$28t-42-2t-4=10\left(3t-4\right)$$

Combine $28t$ and $-2t$ to get $26t$.

$$26t-42-4=10\left(3t-4\right)$$

Subtract $4$ from $-42$ to get $-46$.

$$26t-46=10\left(3t-4\right)$$

Use the distributive property to multiply $10$ by $3t-4$.

$$26t-46=30t-40$$

Subtract $30t$ from both sides.

$$26t-46-30t=-40$$

Combine $26t$ and $-30t$ to get $-4t$.

$$-4t-46=-40$$

Add $46$ to both sides.

$$-4t=-40+46$$

Add $-40$ and $46$ to get $6$.

$$-4t=6$$

Divide both sides by $-4$.

$$t=\frac{6}{-4}$$

Reduce the fraction $\frac{6}{-4}$ to lowest terms by extracting and canceling out $2$.

$$t=-\frac{3}{2}$$