1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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a⋅(b-2)=3b

3(r+2s)=2t-4

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Question

$$140 \div 14 + 55 \times 8 - 72 \times 7 + 16 + 4 + 8 \times 2$$

Evaluate

$-18$

Solution Steps

Divide $140$ by $14$ to get $10$.

$$10+55\times 8-72\times 7+16+4+8\times 2$$

Multiply $55$ and $8$ to get $440$.

$$10+440-72\times 7+16+4+8\times 2$$

Add $10$ and $440$ to get $450$.

$$450-72\times 7+16+4+8\times 2$$

Multiply $72$ and $7$ to get $504$.

$$450-504+16+4+8\times 2$$

Subtract $504$ from $450$ to get $-54$.

$$-54+16+4+8\times 2$$

Add $-54$ and $16$ to get $-38$.

$$-38+4+8\times 2$$

Add $-38$ and $4$ to get $-34$.

$$-34+8\times 2$$

Multiply $8$ and $2$ to get $16$.

$$-34+16$$

Add $-34$ and $16$ to get $-18$.

$$-18$$

Show Solution

Factor

$-18$

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