How to solve 14y = 3 + 2x ^ 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 14y = 3 + 2x ^ 2 | Equatix

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$$14y=3+2x^{2}$$

$y=\frac{x^{2}}{7}+\frac{3}{14}$

The equation is in standard form.

$$14y=2x^{2}+3$$

Divide both sides by $14$.

$$\frac{14y}{14}=\frac{2x^{2}+3}{14}$$

Dividing by $14$ undoes the multiplication by $14$.

$$y=\frac{2x^{2}+3}{14}$$

Divide $3+2x^{2}$ by $14$.

$$y=\frac{x^{2}}{7}+\frac{3}{14}$$

$x=-\frac{\sqrt{28y-6}}{2}$
$x=\frac{\sqrt{28y-6}}{2}$

$x=\frac{\sqrt{28y-6}}{2}$
$x=-\frac{\sqrt{28y-6}}{2}\text{, }y\geq \frac{3}{14}$