How to solve 15(x)^(2)-5ax=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 15(x)^(2)-5ax= | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$15 { x }^{ 2 } -5ax=$$

Factor

$5x\left(3x-a\right)$

Solution Steps

Factor out $5$.

$$5\left(3x^{2}-ax\right)$$

Consider $3x^{2}-ax$. Factor out $x$.

$$x\left(3x-a\right)$$

Rewrite the complete factored expression.

$$5x\left(3x-a\right)$$

Show Solution

Evaluate

$5x\left(3x-a\right)$

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