How to solve 15/4+7/6+17/4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 15/4+7/6+17/4 | Equatix

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Question

$$15/4+7/6+17/4$$

Evaluate

$\frac{55}{6}\approx 9.166666667$

Solution Steps

Least common multiple of $4$ and $6$ is $12$. Convert $\frac{15}{4}$ and $\frac{7}{6}$ to fractions with denominator $12$.

$$\frac{45}{12}+\frac{14}{12}+\frac{17}{4}$$

Since $\frac{45}{12}$ and $\frac{14}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{45+14}{12}+\frac{17}{4}$$

Add $45$ and $14$ to get $59$.

$$\frac{59}{12}+\frac{17}{4}$$

Least common multiple of $12$ and $4$ is $12$. Convert $\frac{59}{12}$ and $\frac{17}{4}$ to fractions with denominator $12$.

$$\frac{59}{12}+\frac{51}{12}$$

Since $\frac{59}{12}$ and $\frac{51}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{59+51}{12}$$

Add $59$ and $51$ to get $110$.

$$\frac{110}{12}$$

Reduce the fraction $\frac{110}{12}$ to lowest terms by extracting and canceling out $2$.

$$\frac{55}{6}$$

Show Solution

Factor

$\frac{5 \cdot 11}{2 \cdot 3} = 9\frac{1}{6} = 9.166666666666666$