How to solve 15=(x)^(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$15= { x }^{ 2 }$$

Solve for x

$x=\sqrt{15}\approx 3.872983346$
$x=-\sqrt{15}\approx -3.872983346$

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=15$$

Take the square root of both sides of the equation.

$$x=\sqrt{15}$$ $$x=-\sqrt{15}$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=15$$

Subtract $15$ from both sides.

$$x^{2}-15=0$$

This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $-15$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.

$$x=\frac{0±\sqrt{0^{2}-4\left(-15\right)}}{2}$$

Square $0$.

$$x=\frac{0±\sqrt{-4\left(-15\right)}}{2}$$

Multiply $-4$ times $-15$.

$$x=\frac{0±\sqrt{60}}{2}$$

Take the square root of $60$.

$$x=\frac{0±2\sqrt{15}}{2}$$

Now solve the equation $x=\frac{0±2\sqrt{15}}{2}$ when $±$ is plus.

$$x=\sqrt{15}$$

Now solve the equation $x=\frac{0±2\sqrt{15}}{2}$ when $±$ is minus.

$$x=-\sqrt{15}$$

The equation is now solved.

$$x=\sqrt{15}$$ $$x=-\sqrt{15}$$

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Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

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Linear Algebra

Chemistry

Example

Question

Solve for x

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Steps Using the Quadratic Formula