$$15\frac{3}{7}\div1\frac{23}{49}$$
$\frac{21}{2}=10.5$
$$\frac{\left(15\times 7+3\right)\times 49}{7\left(1\times 49+23\right)}$$
$$\frac{7\left(3+7\times 15\right)}{23+49}$$
$$\frac{7\left(3+105\right)}{23+49}$$
$$\frac{7\times 108}{23+49}$$
$$\frac{756}{23+49}$$
$$\frac{756}{72}$$
$$\frac{21}{2}$$
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$\frac{3 \cdot 7}{2} = 10\frac{1}{2} = 10.5$
