How to solve 15-2x > 8x+6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 15-2x > 8x+6 | Equatix

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$$15-2x > 8x+6$$

$x<\frac{9}{10}$

Subtract $8x$ from both sides.

$$15-2x-8x>6$$

Combine $-2x$ and $-8x$ to get $-10x$.

$$15-10x>6$$

Subtract $15$ from both sides.

$$-10x>6-15$$

Subtract $15$ from $6$ to get $-9$.

$$-10x>-9$$

Divide both sides by $-10$. Since $-10$ is negative, the inequality direction is changed.

$$x<\frac{-9}{-10}$$

Fraction $\frac{-9}{-10}$ can be simplified to $\frac{9}{10}$ by removing the negative sign from both the numerator and the denominator.

$$x<\frac{9}{10}$$