Solve 15 - (- 3)\{4 - 6 - 2\}; /3\ 5+(-3)*(-6)\

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Question

$$15-(-3)\{4-6-2\}; \div3\{5+(-3)\times(-6)\}$$

Evaluate

$567$

Solution Steps

Multiply $155$ and $-3$ to get $-465$.

$$-465\left(-3\right)\left(4-3\right)+3\left(5\left(-3\right)\left(-3\right)\left(-6\right)-6\right)$$

Multiply $-465$ and $-3$ to get $1395$.

$$1395\left(4-3\right)+3\left(5\left(-3\right)\left(-3\right)\left(-6\right)-6\right)$$

Subtract $3$ from $4$ to get $1$.

$$1395\times 1+3\left(5\left(-3\right)\left(-3\right)\left(-6\right)-6\right)$$

Multiply $1395$ and $1$ to get $1395$.

$$1395+3\left(5\left(-3\right)\left(-3\right)\left(-6\right)-6\right)$$

Multiply $5$ and $-3$ to get $-15$.

$$1395+3\left(-15\left(-3\right)\left(-6\right)-6\right)$$

Multiply $-15$ and $-3$ to get $45$.

$$1395+3\left(45\left(-6\right)-6\right)$$

Multiply $45$ and $-6$ to get $-270$.

$$1395+3\left(-270-6\right)$$

Subtract $6$ from $-270$ to get $-276$.

$$1395+3\left(-276\right)$$

Multiply $3$ and $-276$ to get $-828$.

$$1395-828$$

Subtract $828$ from $1395$ to get $567$.

$$567$$

Show Solution

Factor

$3^{4}\times 7$