Solve 15-(-3)\ 4- overline 6-2 \; /3\ 5+(-3)*(-6)\

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Question

$$15-(-3)\{4-\overline{6-2}\}; \div3\{5+(-3)\times(-6)\}$$

Evaluate

$-77$

Solution Steps

Cancel out $3$ and $3$.

$$15-\left(-\left(4-6-2\right)\left(5-3\left(-6\right)\right)\right)$$

To find the opposite of $4-6-2$, find the opposite of each term.

$$15-\left(-4-\left(-6\right)-\left(-2\right)\right)\left(5-3\left(-6\right)\right)$$

The opposite of $-6$ is $6$.

$$15-\left(-4+6-\left(-2\right)\right)\left(5-3\left(-6\right)\right)$$

Add $-4$ and $6$ to get $2$.

$$15-\left(2-\left(-2\right)\right)\left(5-3\left(-6\right)\right)$$

The opposite of $-2$ is $2$.

$$15-\left(2+2\right)\left(5-3\left(-6\right)\right)$$

Add $2$ and $2$ to get $4$.

$$15-4\left(5-3\left(-6\right)\right)$$

Multiply $-3$ and $-6$ to get $18$.

$$15-4\left(5+18\right)$$

Add $5$ and $18$ to get $23$.

$$15-4\times 23$$

Multiply $4$ and $23$ to get $92$.

$$15-92$$

Subtract $92$ from $15$ to get $-77$.

$$-77$$

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