Question

$$15(y-4)-2(y-9)+\overline{5}(y+6)=0$$

Answer

$$o=(-15*(y-4)+2*(y-9))/(5*e^2*IM*v*r*l*n*(y+6))$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[15(y-4)-2(y-9)+ov{e}^{2}rl\imath n\times 5(y+6)=0\]
Regroup terms.
\[15(y-4)-2(y-9)+5{e}^{2}\imath ovrln(y+6)=0\]
Subtract \(15(y-4)\) from both sides.
\[-2(y-9)+5{e}^{2}\imath ovrln(y+6)=-15(y-4)\]
Add \(2(y-9)\) to both sides.
\[5{e}^{2}\imath ovrln(y+6)=-15(y-4)+2(y-9)\]
Divide both sides by \(5\).
\[{e}^{2}\imath ovrln(y+6)=\frac{-15(y-4)+2(y-9)}{5}\]
Divide both sides by \({e}^{2}\).
\[\imath ovrln(y+6)=\frac{\frac{-15(y-4)+2(y-9)}{5}}{{e}^{2}}\]
Simplify  \(\frac{\frac{-15(y-4)+2(y-9)}{5}}{{e}^{2}}\)  to  \(\frac{-15(y-4)+2(y-9)}{5{e}^{2}}\).
\[\imath ovrln(y+6)=\frac{-15(y-4)+2(y-9)}{5{e}^{2}}\]
Divide both sides by \(\imath \).
\[ovrln(y+6)=\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}}}{\imath }\]
Simplify  \(\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}}}{\imath }\)  to  \(\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath }\).
\[ovrln(y+6)=\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath }\]
Divide both sides by \(v\).
\[orln(y+6)=\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath }}{v}\]
Simplify  \(\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath }}{v}\)  to  \(\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath v}\).
\[orln(y+6)=\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath v}\]
Divide both sides by \(r\).
\[oln(y+6)=\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath v}}{r}\]
Simplify  \(\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath v}}{r}\)  to  \(\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vr}\).
\[oln(y+6)=\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vr}\]
Divide both sides by \(l\).
\[on(y+6)=\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vr}}{l}\]
Simplify  \(\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vr}}{l}\)  to  \(\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrl}\).
\[on(y+6)=\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrl}\]
Divide both sides by \(n\).
\[o(y+6)=\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrl}}{n}\]
Simplify  \(\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrl}}{n}\)  to  \(\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrln}\).
\[o(y+6)=\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrln}\]
Divide both sides by \(y+6\).
\[o=\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrln}}{y+6}\]
Simplify  \(\frac{\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrln}}{y+6}\)  to  \(\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrln(y+6)}\).
\[o=\frac{-15(y-4)+2(y-9)}{5{e}^{2}\imath vrln(y+6)}\]