Solve 15 + (3c + 2)/5 = c/3 + 2/7 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$15+\frac{3c+2}{5}=\frac{c}{3}+\frac{2}{7}$$

Solve for c

$c = -\frac{1587}{28} = -56\frac{19}{28} \approx -56.678571429$

Steps for Solving Linear Equation

Multiply both sides of the equation by $105$, the least common multiple of $5,3,7$.

$$1575+21\left(3c+2\right)=35c+30$$

Use the distributive property to multiply $21$ by $3c+2$.

$$1575+63c+42=35c+30$$

Add $1575$ and $42$ to get $1617$.

$$1617+63c=35c+30$$

Subtract $35c$ from both sides.

$$1617+63c-35c=30$$

Combine $63c$ and $-35c$ to get $28c$.

$$1617+28c=30$$

Subtract $1617$ from both sides.

$$28c=30-1617$$

Subtract $1617$ from $30$ to get $-1587$.

$$28c=-1587$$

Divide both sides by $28$.

$$c=\frac{-1587}{28}$$

Fraction $\frac{-1587}{28}$ can be rewritten as $-\frac{1587}{28}$ by extracting the negative sign.

$$c=-\frac{1587}{28}$$