Question

$$15^{\circ}15^{\prime}15^{\prime\prime}$$

Answer

$$-e^2*r^2*m^2*p*15^(15^prime+p)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{15}^{{15}^{prime}+p}{r}^{2}{\imath }^{2}{m}^{2}{e}^{2}p\]
Use Square Rule: \({i}^{2}=-1\).
\[{15}^{{15}^{prime}+p}{r}^{2}\times -1\times {m}^{2}{e}^{2}p\]
Simplify.
\[{15}^{{15}^{prime}+p}{r}^{2}\times -{m}^{2}{e}^{2}p\]
Regroup terms.
\[-{e}^{2}{r}^{2}{m}^{2}p\times {15}^{{15}^{prime}+p}\]