Question

$$150.12-14.34=dapatmaysolion$$

Answer

$$d=-(135.78*IM)/(a^3*p*t*m*y*s*o^2*l*n)$$

Solution


Regroup terms.
\[150.12-14.34=daaaptmysooln\imath \]
Simplify  \(daaaptmysooln\imath \)  to  \(d{a}^{3}ptmys{o}^{2}ln\imath \).
\[150.12-14.34=d{a}^{3}ptmys{o}^{2}ln\imath \]
Regroup terms.
\[150.12-14.34=\imath d{a}^{3}ptmys{o}^{2}ln\]
Simplify  \(150.12-14.34\)  to  \(135.78\).
\[135.78=\imath d{a}^{3}ptmys{o}^{2}ln\]
Divide both sides by \(\imath \).
\[\frac{135.78}{\imath }=d{a}^{3}ptmys{o}^{2}ln\]
Rationalize the denominator: \(\frac{135.78}{\imath } \cdot \frac{\imath }{\imath }=-135.78\imath \).
\[-135.78\imath =d{a}^{3}ptmys{o}^{2}ln\]
Divide both sides by \({a}^{3}\).
\[-\frac{135.78\imath }{{a}^{3}}=dptmys{o}^{2}ln\]
Divide both sides by \(p\).
\[-\frac{\frac{135.78\imath }{{a}^{3}}}{p}=dtmys{o}^{2}ln\]
Simplify  \(\frac{\frac{135.78\imath }{{a}^{3}}}{p}\)  to  \(\frac{135.78\imath }{{a}^{3}p}\).
\[-\frac{135.78\imath }{{a}^{3}p}=dtmys{o}^{2}ln\]
Divide both sides by \(t\).
\[-\frac{\frac{135.78\imath }{{a}^{3}p}}{t}=dmys{o}^{2}ln\]
Simplify  \(\frac{\frac{135.78\imath }{{a}^{3}p}}{t}\)  to  \(\frac{135.78\imath }{{a}^{3}pt}\).
\[-\frac{135.78\imath }{{a}^{3}pt}=dmys{o}^{2}ln\]
Divide both sides by \(m\).
\[-\frac{\frac{135.78\imath }{{a}^{3}pt}}{m}=dys{o}^{2}ln\]
Simplify  \(\frac{\frac{135.78\imath }{{a}^{3}pt}}{m}\)  to  \(\frac{135.78\imath }{{a}^{3}ptm}\).
\[-\frac{135.78\imath }{{a}^{3}ptm}=dys{o}^{2}ln\]
Divide both sides by \(y\).
\[-\frac{\frac{135.78\imath }{{a}^{3}ptm}}{y}=ds{o}^{2}ln\]
Simplify  \(\frac{\frac{135.78\imath }{{a}^{3}ptm}}{y}\)  to  \(\frac{135.78\imath }{{a}^{3}ptmy}\).
\[-\frac{135.78\imath }{{a}^{3}ptmy}=ds{o}^{2}ln\]
Divide both sides by \(s\).
\[-\frac{\frac{135.78\imath }{{a}^{3}ptmy}}{s}=d{o}^{2}ln\]
Simplify  \(\frac{\frac{135.78\imath }{{a}^{3}ptmy}}{s}\)  to  \(\frac{135.78\imath }{{a}^{3}ptmys}\).
\[-\frac{135.78\imath }{{a}^{3}ptmys}=d{o}^{2}ln\]
Divide both sides by \({o}^{2}\).
\[-\frac{\frac{135.78\imath }{{a}^{3}ptmys}}{{o}^{2}}=dln\]
Simplify  \(\frac{\frac{135.78\imath }{{a}^{3}ptmys}}{{o}^{2}}\)  to  \(\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}}\).
\[-\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}}=dln\]
Divide both sides by \(l\).
\[-\frac{\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}}}{l}=dn\]
Simplify  \(\frac{\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}}}{l}\)  to  \(\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}l}\).
\[-\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}l}=dn\]
Divide both sides by \(n\).
\[-\frac{\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}l}}{n}=d\]
Simplify  \(\frac{\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}l}}{n}\)  to  \(\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}ln}\).
\[-\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}ln}=d\]
Switch sides.
\[d=-\frac{135.78\imath }{{a}^{3}ptmys{o}^{2}ln}\]