How to solve 157 imes347

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 157\times347 | Equatix

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Question

$$157 \times 347$$

Evaluate

$54479$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}157\\\underline{\times\phantom{99}347}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 157 with 7. Write the result 1099 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}157\\\underline{\times\phantom{99}347}\\\phantom{\times9}1099\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 157 with 4. Write the result 628 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}157\\\underline{\times\phantom{99}347}\\\phantom{\times9}1099\\\phantom{\times9}628\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 157 with 3. Write the result 471 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}157\\\underline{\times\phantom{99}347}\\\phantom{\times9}1099\\\phantom{\times9}628\phantom{9}\\\underline{\phantom{\times}471\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}157\\\underline{\times\phantom{99}347}\\\phantom{\times9}1099\\\phantom{\times9}628\phantom{9}\\\underline{\phantom{\times}471\phantom{99}}\\\phantom{\times}54479\end{array}$$

Show Solution

Factor

$157\times 347$