How to solve 1592 > 82/24-32

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1592 > 82/24-32 | Equatix

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a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

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$$1592 > 82/24-32$$

Verify

$\text{true}$

Solution Steps

Reduce the fraction $\frac{82}{24}$ to lowest terms by extracting and canceling out $2$.

$$1592>\frac{41}{12}-32$$

Convert $32$ to fraction $\frac{384}{12}$.

$$1592>\frac{41}{12}-\frac{384}{12}$$

Since $\frac{41}{12}$ and $\frac{384}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$1592>\frac{41-384}{12}$$

Subtract $384$ from $41$ to get $-343$.

$$1592>-\frac{343}{12}$$

Convert $1592$ to fraction $\frac{19104}{12}$.

$$\frac{19104}{12}>-\frac{343}{12}$$

Compare $\frac{19104}{12}$ and $-\frac{343}{12}$.

$$\text{true}$$

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