Question

$$16 a ^ { 3 } b ^ { 3 } - 2 c ^ { 3 }$$

Answer

$$16*b^4*a^3-2*c^3$$

Solution


Regroup terms.
\[16b{b}^{3}{a}^{3}-2{c}^{3}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[16{b}^{1+3}{a}^{3}-2{c}^{3}\]
Simplify  \(1+3\)  to  \(4\).
\[16{b}^{4}{a}^{3}-2{c}^{3}\]