$$16 { x }^{ 4 } -4 { x }^{ 2 } +4x-1$$
$16x^{4}-\left(2x-1\right)^{2}$
$4\left(x-\frac{-\sqrt{5}-1}{4}\right)\left(x-\frac{\sqrt{5}-1}{4}\right)\left(4x^{2}-2x+1\right)$
