Solve 16/2 * [8 - 3(4 - 2)] + 1 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$16\div2\times[8-3\times(4-2)]+1$$

Evaluate

$17$

Solution Steps

Divide $16$ by $2$ to get $8$.

$$8\left(8-3\left(4-2\right)\right)+1$$

Subtract $2$ from $4$ to get $2$.

$$8\left(8-3\times 2\right)+1$$

Multiply $3$ and $2$ to get $6$.

$$8\left(8-6\right)+1$$

Subtract $6$ from $8$ to get $2$.

$$8\times 2+1$$

Multiply $8$ and $2$ to get $16$.

$$16+1$$

Add $16$ and $1$ to get $17$.

$$17$$

Factor

$17$